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104. 二叉树的最大深度
BFS
js
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var maxDepth = function(root) {
let maxDepth = 0
// 树为空的时候
if (root === null) return maxDepth
// 定义一个队列
let queue = []
let count = 0
queue.push(root)
while (queue.length > 0) {
// 获取这一层的长度
let size= queue.length
// 遍历这一层的内容
while (size > 0){
let node = queue.shift()
size--
if(node.left || node.right) {
if(node.left !== null) queue.push(node.left)
if(node.right !== null) queue.push(node.right)
}
}
maxDepth++
}
return maxDepth
};
DFS
js
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var maxDepth = function(root) {
// 树为空的时候
if (root === null) return 0
let leftDep = maxDepth(root.left)
let rightDep = maxDepth(root.right)
return Math.max(leftDep, rightDep)+1
};